spirit/classic/example/fundamental/parse_tree_calc1.cpp

/*=============================================================================
    Copyright (c) 2001-2003 Daniel Nuffer
    http://spirit.sourceforge.net/

    Use, modification and distribution is subject to the Boost Software
    License, Version 1.0. (See accompanying file LICENSE_1_0.txt or copy at
    http://www.boost.org/LICENSE_1_0.txt)
=============================================================================*/
///////////////////////////////////////////////////////////////////////////////
//
//  Demonstrates parse trees. This is discussed in the
//  "Trees" chapter in the Spirit User's Guide.
//
///////////////////////////////////////////////////////////////////////////////
#define BOOST_SPIRIT_DUMP_PARSETREE_AS_XML

#include <boost/spirit/include/classic_core.hpp>
#include <boost/spirit/include/classic_parse_tree.hpp>
#include <boost/assert.hpp>

#include <iostream>
#include <stack>
#include <functional>
#include <string>

#ifdef BOOST_SPIRIT_DUMP_PARSETREE_AS_XML
#include <boost/spirit/include/classic_tree_to_xml.hpp>
#include <map>
#endif

////////////////////////////////////////////////////////////////////////////
// This example shows how to use a parse tree
using namespace std;
using namespace BOOST_SPIRIT_CLASSIC_NS;

// Here's some typedefs to simplify things
typedef char const*         iterator_t;
typedef tree_match<iterator_t> parse_tree_match_t;
typedef parse_tree_match_t::const_tree_iterator iter_t;

typedef pt_match_policy<iterator_t> match_policy_t;
typedef scanner_policies<iteration_policy, match_policy_t, action_policy> scanner_policy_t;
typedef scanner<iterator_t, scanner_policy_t> scanner_t;
typedef rule<scanner_t> rule_t;

//  grammar rules
rule_t expression, term, factor, integer;

////////////////////////////////////////////////////////////////////////////
// Here's the function prototypes that we'll use.  One function for each
// grammar rule.
long evaluate(const tree_parse_info<>& info);
long eval_expression(iter_t const& i);
long eval_term(iter_t const& i);
long eval_factor(iter_t const& i);
long eval_integer(iter_t const& i);

long evaluate(const tree_parse_info<>& info)
{
    return eval_expression(info.trees.begin());
}

// i should be pointing to a node created by the expression rule
long eval_expression(iter_t const& i)
{
    parser_id id = i->value.id();
    BOOST_ASSERT(id == expression.id()); // check the id

    // first child points to a term, so call eval_term on it
    iter_t chi = i->children.begin();
    long lhs = eval_term(chi);
    for (++chi; chi != i->children.end(); ++chi)
    {
        // next node points to the operator.  The text of the operator is
        // stored in value (a vector<char>)
        char op = *(chi->value.begin());
        ++chi;
        long rhs = eval_term(chi);
        if (op == '+')
            lhs += rhs;
        else if (op == '-')
            lhs -= rhs;
        else
            BOOST_ASSERT(0);
    }
    return lhs;
}

long eval_term(iter_t const& i)
{
    parser_id id = i->value.id();
    BOOST_ASSERT(id == term.id());

    iter_t chi = i->children.begin();
    long lhs = eval_factor(chi);
    for (++chi; chi != i->children.end(); ++chi)
    {
        char op = *(chi->value.begin());
        ++chi;
        long rhs = eval_factor(chi);
        if (op == '*')
            lhs *= rhs;
        else if (op == '/')
            lhs /= rhs;
        else
            BOOST_ASSERT(0);
    }
    return lhs;
}

long eval_factor(iter_t const& i)
{
    parser_id id = i->value.id();
    BOOST_ASSERT(id == factor.id());

    iter_t chi = i->children.begin();
    id = chi->value.id();
    if (id == integer.id())
        return eval_integer(chi->children.begin());
    else if (*(chi->value.begin()) == '(')
    {
        ++chi;
        return eval_expression(chi);
    }
    else if (*(chi->value.begin()) == '-')
    {
        ++chi;
        return -eval_factor(chi);
    }
    else
    {
        BOOST_ASSERT(0);
        return 0;
    }
}

long eval_integer(iter_t const& i)
{
    // extract integer (not always delimited by '\0')
    string integer(i->value.begin(), i->value.end());

    return strtol(integer.c_str(), 0, 10);
}

////////////////////////////////////////////////////////////////////////////
int
main()
{

    //  Start grammar definition
    integer     =   lexeme_d[ token_node_d[ (!ch_p('-') >> +digit_p) ] ];
    factor      =   integer
                |   '(' >> expression >> ')'
                |   ('-' >> factor);
    term        =   factor >>
                    *(  ('*' >> factor)
                      | ('/' >> factor)
                    );
    expression  =   term >>
                    *(  ('+' >> term)
                      | ('-' >> term)
                    );
    //  End grammar definition


    cout << "/////////////////////////////////////////////////////////\n\n";
    cout << "\t\tThe simplest working calculator...\n\n";
    cout << "/////////////////////////////////////////////////////////\n\n";
    cout << "Type an expression...or [q or Q] to quit\n\n";

    string str;
    while (getline(cin, str))
    {
        if (str.empty() || str[0] == 'q' || str[0] == 'Q')
            break;

        const char* first = str.c_str();

        tree_parse_info<> info = pt_parse(first, expression);

        if (info.full)
        {
#if defined(BOOST_SPIRIT_DUMP_PARSETREE_AS_XML)
            // dump parse tree as XML
            std::map<parser_id, std::string> rule_names;
            rule_names[integer.id()] = "integer";
            rule_names[factor.id()] = "factor";
            rule_names[term.id()] = "term";
            rule_names[expression.id()] = "expression";
            tree_to_xml(cout, info.trees, first, rule_names);
#endif

            // print the result
            cout << "parsing succeeded\n";
            cout << "result = " << evaluate(info) << "\n\n";
        }
        else
        {
            cout << "parsing failed\n";
        }
    }

    cout << "Bye... :-) \n\n";
    return 0;
}